Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 95: 51


73.7 ft

Work Step by Step

The height of the tower (label it with a) is a leg of a right triangle, opposite to the angle $A=38^{o}20^{\prime}$ The side b = 93.2 is adjacent to A. (SOHCAHTOA) We use $\displaystyle \tan A=\frac{a}{b}$ and solve for a: $a=b\cdot\tan A$ $=93.2\cdot\tan 38^{o}20^{\prime}\approx$73.6930053432$\approx 73.7$ ft
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