Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 95: 46


$A=19^{o}25^{\prime}$ $B=70^{o}35^{\prime}$ $c=390.28$

Work Step by Step

$a$ is the side opposite to A, b is adjacent to it, $a=129.7, b=368.1$ $\displaystyle \tan A=\frac{a}{b}=\frac{129.7}{3681}$ $ A\displaystyle \approx\tan^{-1}(\frac{129.7}{368.1})\approx$19.409904444$8^{o}\approx 19^{o}25^{\prime}$ $A+B=90^{\mathrm{o}}$ $19^{o}25^{\prime}+B=90^{\mathrm{o}}$ $B=90^{\mathrm{o}}-19^{o}25^{\prime}=70^{o}35^{\prime}$ $\displaystyle \sin A=\frac{a}{c}$ $ c=\displaystyle \frac{a}{\sin A}=\frac{129.7}{\sin 19.4099}\approx$390.281650954$\approx 390.28$
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