Answer
$y=(\tan15)(x-5)$
Work Step by Step
Using the instructions in the question, we know that the equation of a line passing through the point $(a,0)$ and making an angle $\theta$ with the x-axis is $y=(\tan\theta)(x-a)$.
The question gives us the point $(5,0)$ and angle $15^{\circ}$, which we can substitute into the equation to get our answer!
$\theta = 15^{\circ}$ and $a=5$
$y=(\tan\theta)(x-a)$
$y=(\tan15)(x-5)$
