Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 90: 45

$y=(\tan35)(x-25)$

Using the instructions in the question, we know that the equation of a line passing through the point $(a,0)$ and making an angle $\theta$ with the x-axis is $y=(\tan\theta)(x-a)$. The question gives us the point $(25,0)$ and angle $35^{\circ}$, which we can substitute into the equation to get our answer! $\theta = 35^{\circ}$ and $a=25$ $y=(\tan\theta)(x-a)$ $y=(\tan35)(x-25)$