#### Answer

Accounting for the curvature of the earth, Mt. Everest would appear shorter than it actually is being over 100 miles away.
22,357 ft $\lt$ 29,000 ft

#### Work Step by Step

Total Mt. Everest height = T $\approx$ 29,000 ft
Distance away = 100 miles = 528,000 ft
TOA = $\tan\theta$ = $\frac{Opposite}{Adjacent}$
$\tan\theta$ = $\frac{29,000}{528,000}$
$\theta$ = $\tan^{-1}(\frac{29,000}{528,000})$
$\theta$ = 3.144 $^{\circ}$
Plugging this value, $\theta$, into part (a), you see that the height appears smaller than it normally would.
$\sin\theta$ = $\frac{P}{h}$
$\sin3.14^{\circ}$ = $\frac{P}{142,631}$
P = $142,631\times\sin3.14^{\circ}$
P = 7,812.7 ft
T = 7,812.7 + 14,545.0
T = 22,357.7 ft
22,357 ft $\lt$ 29,000 ft