Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 81: 57

$\angle A = 42.18^{\circ}$

Work Step by Step

Known: Length of shadow = L = 34.09 meters Height of building = h = 37.62 meters Unknown: Angle of elevation of Sun = A = ? Formulas: $\tan A$ = $\frac{Opposite A}{Adjacent A}$ = $\frac{L}{h}$ Calculation: $\tan A$ = $\frac{34.09}{37.62}$ $A = \tan^{-1}(\frac{34.09}{37.62})$ Final Answer: $\angle A = 42.18^{\circ}$

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