Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 81: 61a

Answer

Total height of Mt. Everest = T = 29,003.8 ft

Work Step by Step

To start, we break down what we know, and what we need to find. Things we know: Altitude = s = 14,545 ft Straight-line distance = h = 27.0134 miles h (in feet) = 27.0134 miles $\times$ 5,280 $\frac{feet}{miles}$ = 142,631 ft angle u = $\theta$ = 5.82$^{\circ}$ Things we need to find: Partial height of Mt. Everest = P Total height of Mt. Everest = T = P + s To find the partial height, P, of Mt. Everest, we can assume that the straight-line distance, h, is the hypotenuse in a triangle with angle, u. Therefore: $\sin\theta$ = $\frac{P}{h}$ $\sin5.82^{\circ}$ = $\frac{P}{142,631}$ P = $142,631\times\sin5.82^{\circ}$ P = 14,463.3 ft T = 14,463.3 + 14,545.0 T = 29,003.8 ft
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