## Trigonometry (11th Edition) Clone

225$^{\circ}$ 315$^{\circ}$
1) Since cscθ is negative, θ must lie in quadrants III or IV. Since the absolute value of cscθ is $\sqrt 2$, the reference angle, θ must be 45°. 2) The quadrant III angle θ equals 180$^{\circ}$ +45$^{\circ}$ =225$^{\circ}$ and the quadrant IV angle θ equals 360$^{\circ}$ - 45$^{\circ}$ = 315$^{\circ}$.