Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 63: 63

Answer

$120^{\circ}$ and $300^{\circ}$

Work Step by Step

1. Since $tan$ $\theta$ is negative, $\theta$ must be in quadrant II or IV. 2.. The absolute value of $\tan\theta$ is $\sqrt 3$, so the reference angle is $60^{\circ}$, so the other angles must be: $180^{\circ} - 60^{\circ} = 120^{\circ}$ $360^{\circ} - 60^{\circ} = 300 ^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.