## Trigonometry (11th Edition) Clone

120$^{\circ}$ 240$^{\circ}$
1)Since cosθ is negative, θ must lie in quadrants II or III. Since the absolute value of cosθ is $\frac{1}{2}$ the reference angle, θ must be 60° 2)The quadrant II angle θ equals 180$^{\circ}$ - 60$^{\circ}$ = 120$^{\circ}$ and the quadrant III angle θ equals 180$^{\circ}$ + 60$^{\circ}$ = 240$^{\circ}$