Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 62: 40


$\tan$ -1020$^{\circ}$ = $\sqrt3$

Work Step by Step

$\cos$ -1020$^{\circ}$ First, lets find the coterminal angle. -1020$^{\circ}$ - 3(360$^{\circ}$) = 60$^{\circ}$ Next, we find the reference angle. $\theta$$^{1}$ = 60$^{\circ}$ Since the coterminal angle is in Quadrant I, $\tan$ is negative. Therefore: $\tan$ 60$^{\circ}$ = $\sqrt3$
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