Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 62: 18

Answer

$\tan$240^{\circ} = $\sqrt3$ $\cot$240^{\circ} = $\frac{\sqrt3}{3}$

Work Step by Step

240^{\circ} We must use the reference angle of the given angle to determine the trigonometric functions. The reference angle of $\tan$240^{\circ} = $\frac{-\sqrt3}{-1}$ = $\sqrt3$ $\cot$240^{\circ} = $\frac{-1}{-\sqrt3}$ = $\frac{1}{\sqrt3}$ = $\frac{\sqrt3}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.