Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 62: 12

Answer

$\sin$ 45$^{\circ}$ = $\frac{\sqrt2}{2}$ $\cos$ 45$^{\circ}$ = $\frac{\sqrt2}{2}$ $\sec$ 45$^{\circ}$ = $\sqrt2$ $\csc$ 45$^{\circ}$ = $\sqrt2$

Work Step by Step

$\sin$ 45$^{\circ}$ = $\frac{1}{\sqrt2}$ = $\frac{\sqrt2}{2}$ $\cos$ 45$^{\circ}$ = $\frac{1}{\sqrt2}$ = $\frac{\sqrt2}{2}$ $\sec$ 45$^{\circ}$ = $\frac{\sqrt2}{1}$ = $\sqrt2$ $\csc$ 45$^{\circ}$ = $\frac{\sqrt2}{1}$ = $\sqrt2$
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