## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 53: 9

#### Answer

$\sin$A = $\frac{n}{p}$ $\cos$A = $\frac{m}{p}$ $\tan$A = $\frac{n}{m}$

#### Work Step by Step

$\sin$A = $\frac{perpendicular}{hypotenuse}$ $\cos$A = $\frac{base}{hypotenuse}$ $\tan$A = $\frac{perpendicular}{base}$

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