Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 53: 8

Answer

$\sin$ A = $\frac{45}{53}$ $\cos$ A = $\frac{28}{53}$ $\tan$ A = $\frac{45}{28}$

Work Step by Step

$\sin$ = $\frac{perpendicular}{hypotenuse}$ $\cos$ = $\frac{base}{hypotenuse}$ $\tan$ = $\frac{perpendicular}{base}$
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