Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 53: 5

Answer

$\csc \theta = \frac{1}{\sin\theta}$ $\csc 60^{\circ}= \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt 3}{2}}= \frac{2}{\sqrt 3}$

Work Step by Step

$\csc \theta = \frac{1}{\sin\theta}$ (Inverse property) $\csc 60^{\circ}= \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt 3}{2}}= \frac{2}{\sqrt 3}$ (Special angle)
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