Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 53: 5


$\csc \theta = \frac{1}{\sin\theta}$ $\csc 60^{\circ}= \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt 3}{2}}= \frac{2}{\sqrt 3}$

Work Step by Step

$\csc \theta = \frac{1}{\sin\theta}$ (Inverse property) $\csc 60^{\circ}= \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt 3}{2}}= \frac{2}{\sqrt 3}$ (Special angle)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.