Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix D - Graphing Techniques - Exercises - Page 448: 20

Answer

Appendix D - 14 (Answer) See Graph I
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Work Step by Step

Appendix D - 14 (Solution) For $y = \frac{1}{3} x^2$, When $x = 6, y = 12;$ $x = 3, y = 3;$ $x = 0, y = 0;$ $x = −3, y = 3;$ $x = −6, y = 12$ Domain = $(−\infty, \infty)$ Range = $[0, \infty)$ See Graph I
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