## Trigonometry (11th Edition) Clone

For $y = -2|x|,$ when $x=1, y=-2, x=0, y=0$ and $x=-1, y=-2$ The curve passes through $(1,-2), (0,0)$ and $(-1,-2)$. Since the graph of $y=-2|x|$ is vertically stretched twice of the graph of $y=|x|$ and reflected across the x-axis, graph "E" is the correct sketching.