## Trigonometry (11th Edition) Clone

Published by Pearson

# Appendix D - Graphing Techniques - Exercises - Page 448: 12d

#### Answer

Graph "D" is the correct sketching.

#### Work Step by Step

For $y = 2|x|,$ when $x=0, y=0, x=1, y=2$ and $x=-1, y=2$ The curve passes through $(0,0), (1,2)$ and $(-1,2)$. Since the graph of $y=2|x|$ is vertically stretched twice of the graph of $y=|x|$, graph "D" is the correct sketching.

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