Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix A - Equations and Inequalities - Page 420: 43



Work Step by Step

According to the square root property, if $x^{2}=16$ then $x=\sqrt (16)=4$ or $x=-\sqrt (16)=-4$ Therefore, the solution set is{$-4,+4$} or {$\pm4$}
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