Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix A - Equations and Inequalities - Page 420: 33



Work Step by Step

$5x^{2}-3x-2=0$ $5x^{2}-5x+2x-2=0$ $5x(x-1)+2(x-1)=0$ $(x-1)(5x+2)=0$ $(x-1)=0$ or $(5x+2)=0$ $x=1$ or $x=-\frac{2}{5}$ Check: Substituting $x=1$ in the equation, $5(1)^{2}-3(1)-2=0$ $5-3-2=0$ $5-5=0$ $0=0$ Substituting $x=-\frac{2}{5}$ in the equation, $5(-\frac{2}{5})^{2}-3(-\frac{2}{5})-2=0$ $\frac{20}{25}+\frac{6}{5}-2=0$ $\frac{4}{5}+\frac{6}{5}-2=0$ $\frac{10}{5}-2=0$ $2-2=0$ $0=0$ Both values check and the solution set is {$-\frac{2}{5},1$}
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