Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix A - Equations and Inequalities - Page 420: 37


{$-10,+10$} or {$\pm 10$}

Work Step by Step

$x^{2}-100=0$ $(x)^{2}-(10)^{2}=0$ $(x+10)(x-10)=0$ $(x+10)=0$ or $(x-10)=0$ $x=-10$ or $x=10$ Check: Substituting $x=-10$ in the equation, $(-10)^{2}-(10)^{2}=0$ $100-100=0$ $0=0$ Substituting $x=10$ in the equation, $(10)^{2}-(10)^{2}=0$ $100-100=0$ $0=0$ Both values check and the solution set is {$-10,+10$} or {$\pm10$}
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