Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 7 - Review - Review Exercises - Page 394: 11c

Answer

0.2476

Work Step by Step

Let's find the z-scores for 110 and 140: $z=\frac{X-μ}{σ}=\frac{110-100}{15}=0.67$ $z=\frac{X-μ}{σ}=\frac{140-100}{15}=2.67$ According to Table V, the area to the left of the standard normal curve for a z-score equal to 0.67 is 0.7486. According to Table V, the area to the left of the standard normal curve for a z-score equal to 2.67 is 0.9962. The area of the standard normal curve between the z-scores 0.67 and 2.67 is the difference between the area to the left of the standard normal curve for a z-score equal to 2.67 and the area to the left of the standard normal curve for a z-score equal to 0.67: $0.9962-0.7486=0.2476$
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