Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 7 - Review - Review Exercises - Page 394: 10c

Answer

$0.8613$

Work Step by Step

Let's find the z-scores for 65,000 and 80,000 miles: $z=\frac{X-μ}{σ}=\frac{65000-70000}{4400}=-1.14$ $z=\frac{X-μ}{σ}=\frac{80000-70000}{4400}=2.27$ According to Table V, the area to the left of the standard normal curve for a z-score equal to -1.14 is 0.1271. According to Table V, the area to the left of the standard normal curve for a z-score equal to 2.27 is 0.9884. The area of the standard normal curve between the z-scores -1.14 and 2.27 is the difference between the area to the left of the standard normal curve for a z-score equal to 2.27 and the area to the left of the standard normal curve for a z-score equal to -1.14: $0.9884-0.1271=0.8613$
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