Answer
130.75
Work Step by Step
A child in the 98th percentile has an intelligence score greater than 98% of all children.
98% = 0.98
According to Table V, the z-score which gives the closest value to 0.98 is 2.05
Let's find the intelligence score for the given z-score:
$z=\frac{X-μ}{σ}$
$2.05=\frac{X-100}{15}$
$2.05\times15=X-100$
$30.75=X-100$
$X=30.75+100=130.75$
