Answer
$P(29)=0.334$
It is close to the results obtained in b).
(Other simulations are possible, but it is not expected that the results are going to be very different)
Work Step by Step
$P(x)={}_nC_{x}~p^x~(1-p)^{n-x}$
$n = 30$, $p=0.98$ and $1-p=0.02$
$P(29)={}_{30}C_{29}\times0.98^{29}\times0.02^1=\frac{30!}{29!\times1!}\times0.98^{29}\times0.02=0.334$
