Chapter 6 - Section 6.2 - Assess Your Understanding - Applying the Concepts - Page 345: 45a

Mean = 225 Standard Deviation $\approx$ 11.1

i) Mean of a binomial experiment = np np = 0.45 x 500 = 225 ii) Standard Deviation of a binomial experiment is given by $\sqrt {np(1-p)}$ $\sqrt {np(1-p)}$ $\sqrt {500 \times 0.45\times(1-0.45)}$ = 11.12429773 $\approx$ 11.1