Answer
$P(3)=0.0596$
Work Step by Step
$P(x)={}_nC_{x}~p^x~(1-p)^{n-x}$
n = 20, p = 5% = 0.05 and 1 - p = 95% = 0.95
$P(3)={}_{20}C_{3}\times0.05^3\times0.95^{17}=\frac{20!}{3!\times17!}\times0.05^3\times0.95^{17}=0.0596$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 6 - Section 6.2 - Assess Your Understanding - Applying the Concepts - Page 345: 38a
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