Answer
See the picture.
Work Step by Step
Total number of games: $19+12+13=44$
The relative frequency for "3 sets" is $\frac{19}{44}\approx0.4318$
The relative frequency for "4 sets" is $\frac{12}{44}\approx0.2727$
The relative frequency for "5 sets" is $\frac{13}{44}\approx0.2955$
