Answer
$P(Junior)=\frac{112}{449}\approx0.2494$
Work Step by Step
$N(Senior)=92$
$N(Junior)=112$
$N(Sophomore)=125$
$N(Freshman)=120$
The sample space: $92+112+125+120=449$ students. So, $N(S)=449$
1) a single event
2) relative frequency
Use the Empirical Approach (page 258):
$P(Junior)=\frac{N(Junior)}{N(S)}=\frac{112}{449}\approx0.2494$
