Answer
P(four or more) $=0.896$
If we randomly select 1000 U.S. housing units, we would expect about 896 to be a housing unit that has four or more rooms.
Work Step by Step
The event "a housing unit has four or more rooms" is the complement of the event "a housing unit has one, two or three rooms". So:
P(four or more) = 1 - P(one or two or three) =
$=1-P(one)-P(two)-P(three)=1-0.005-0.011-0.088=0.896$
