Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.2 - Assess Your Understanding - Applying the Concepts - Page 277: 25d

Answer

$P(\text{not a gun}) = 0.329$ If we select 1000 murder cases in 2009, we would expect about 329 of them not to be the result of a gun.

Work Step by Step

The event: "murder resulted from a weapon other than a gun" is the complement of "murder resulted from a gun". A gun may be a handgun, a rifle, a shotgun or an unknown firearm. $P(gun)= P(\text{handgun or rifle or shotgun or unknown firearm})=P(handgun)+P(rifle)+P(shotgun)+P(unknown firearm)=0.473+0.026+0.031+0.141=0.671.$ $P(\text{not a gun}) = 1 - P(gun)=1-0.671=0.329$
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