Answer
F
Work Step by Step
Suppose that we repeat this experiment (tossing a coin twice) 900 times:
- We expect that HH will occur $\frac{1}{9}\times900=100$ times. So, $100\times2=200$ heads will be observed, in this case.
- We expect that TH will occur $\frac{2}{9}\times900=200$ times. So, $200\times1=200$ tails and $200\times1=200$ heads will be observed, in this case.
- We expect that HT will occur $\frac{2}{9}\times900=200$ times. So, $200\times1=200$ tails and $200\times1=200$ heads will be observed, in this case.
- We expect that TT will occur $\frac{4}{9}\times900=400$ times. So, $400\times2=800$ tails will be observed, in this case.
- Total of heads we expect to observe: $200+200+200=600$
- Total of tails we expect to observe: $200+200+800=1200$
We conclude that tails is twice as likely to occur as heads.
