Answer
A, B, C, F
Work Step by Step
For A, B, C, F each probability is greater than or equal to 0 and less than or equal to 1, but not for D: $P(TH) = -\frac{1}{2}$
For A, B, C, F the sum of the probabilities of all outcomes is equal 1, but not for E: $P(HH)+P(HT)+P(TH)+P(TT)=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{1}{8}=\frac{7}{8}$
See Rules of Probabilities.
