Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 242: 5.34e

Answer

$p(92\leq x\leq 96)=.1498$

Work Step by Step

$z_0=\frac{x-\mu}{\sigma}=\frac{92-100}{8}=-1$ $z_0=\frac{x-\mu}{\sigma}=\frac{96-100}{8}=-.5$ According to table IV, page 773: $p(0\lt z\lt 1)=.3413$ $p(0\lt z\lt .5)=.1915$ $p(92\leq x\leq 96)=p(-1\leq z\leq -.5)=p(-1\leq z\lt0)-p(-.5\leq z\leq0)=p(0\lt z\leq1)-p(0\leq z\leq.5)=.3413-.1915=.1498$
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