Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 242: 5.34c

Answer

$p(x\leq 92)=.1587$

Work Step by Step

$z_0=\frac{x-\mu}{\sigma}=\frac{92-100}{8}=-1$ According to table IV, page 773: $p(0\lt z\lt 1)=.3413$ $p(x\leq 92)=p(z\leq -1)=p(z\gt1)=p(z\gt0)-p(z\gt1)=.5-.3413=.1587$
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