Answer
$p(x\geq7.62)=.9545$
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{7.62-11}{2}=-1.69$
$p(x\geq7.62)=p(z\geq-1.69)=p(-1.69\leq z\lt0)+p(z\geq0)=p(0\lt z\leq1.69)+p(z\geq0)=.4545+.5=.9545$
According to Table IV, page 773:
$p(0\lt z\leq1.69)=.4545$