Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 242: 5.31f

Answer

$p(x\geq7.62)=.9545$

Work Step by Step

$z=\frac{x-\mu}{\sigma}=\frac{7.62-11}{2}=-1.69$ $p(x\geq7.62)=p(z\geq-1.69)=p(-1.69\leq z\lt0)+p(z\geq0)=p(0\lt z\leq1.69)+p(z\geq0)=.4545+.5=.9545$ According to Table IV, page 773: $p(0\lt z\leq1.69)=.4545$
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