Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Applying the Concepts - Basic - Page 205: 4.63d

Answer

The interval is from 30.2 to 49.8.

Work Step by Step

$\mu=np=100(.4)=40$ $\sigma=\sqrt {npq}=\sqrt {100(.4)(.6)}=4.90$ $\mu-2\sigma=40-2(4.90)=30.2$ $\mu+2\sigma=40+2(4.90)=49.8$
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