Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 6 - Supplementary Exercises - Page 264: 6.58

Answer

3.72 %

Work Step by Step

We find: $P(x \lt 9 )$ = $P(z \lt \frac{9-9.125}{.06} )$ = $P(z\lt -2.083)$ = 0.0186 $P(x \gt 9.25)$ = $P(z \gt \frac{9.25-9.125}{.06} )$ = $P(z \gt 2.083)$ = 0.0186 Probability of discarded rods = 0.0186+0.0186 = 0.0372*100 =3.72 %
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