Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 6 - Supplementary Exercises - Page 264: 6.55

Answer

0

Work Step by Step

Μ=16, σ=0.18 a. $P(16.20 \leq x \leq 16.50 )$ = $P(\frac{16.20-16}{0.18} \leq z \leq \frac{16.50-16}{0.18})$ =$P(1.1111\leq x \leq 2.7778 )$ =0.9973-0.8667= 0.1306 b. $P(x \lt 15.70 )$ = $P(z \lt \frac{15.70-16}{.18} )$ = $P(z \lt -1.6667 )$ = 0.0478 0.0478*100 = 4.78% c. $P(x \lt 15.20 )$ = $P(z \lt \frac{15.20-16}{.18} )$ = $P(z \lt -4.4444 )$ = 0 It is impossible to be 15.20 ounces, because the probability shown is 0.
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