Answer
1.24 percent
Work Step by Step
Μ=50, σ=0.06
$P(x \lt 49.85 )$ = $P(z \lt \frac{49.85-50}{.06} )$ = $P(z \lt 2.5)$ = 0.0062
$P(x \gt 50.15 )$ = $P(z \gt \frac{50.15-50}{.06} )$ = $P(z \lt 2.5)$ = 0.0062
Probability of discarded rods = 0.0062+0.0062 = 0.0124 *100 = 1.24%
