Answer
N=20, r=4, n =6
a. x=1
$P(1) = \frac{4C_1\times 16C_5}{20C_6}$ =0.4508
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b.x=0
P(x=0) = $\frac{4C_0\times 16C_6}{20C_6}$ =0.2066
c.$P(x \leq 2) $= $\frac{4C_0\times 16C_6}{20C_6}+\frac{4C_1\times 16C_5}{20C_6}$ + $\frac{4C_2\times 16C_4}{20C_6}$=0.0263
Work Step by Step
see above.