Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 5 - Section 5.5 - The Hypergeometric Probability Distribution - Exercises - Page 206: 5.42

Answer

N=8, r=3, n =4 a. x=2 $P(2) = \frac{3C_2\times 5C_2}{8C_4}$ =0.4286 b. $P(x=0) = \frac{3C_0\times 5C_4}{8C_4}$ =0.0717 c. $P(x\leq1) = \frac{3C_0\times 5C_4}{8C_4}+\frac{3C_1\times 5C_3}{8C_4}$ =0.5

Work Step by Step

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