Answer
$\mu=189$
$\sigma^2=69.93$
$\sigma=8.36$
Work Step by Step
Given $p=0.63, n=300$,
mean=$\mu=np=189$
variance=$\sigma^2=np(1-p)=69.93$
standard deviation=$\sigma=\sqrt {69.9}=8.36$
Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition
by Bluman, Allan
Published by
McGraw-Hill Education
ISBN 10:
0078136334
ISBN 13:
978-0-07813-633-7
Chapter 5 - Discrete Probability Distributions - Review Exercises - Section 5-3 - Page 305: 18
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