Answer
$\mu=120$
$\sigma^2=24$
$\sigma=4.9$
Work Step by Step
We have $p=0.8$ and $n=150$
mean=$\mu=np=120$
variance=$\sigma^2=np(1-p)=24$
standard deviation=$\sigma=\sqrt {np(1-p)}=4.9$
Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition
by Bluman, Allan
Published by
McGraw-Hill Education
ISBN 10:
0078136334
ISBN 13:
978-0-07813-633-7
Chapter 5 - Discrete Probability Distributions - Review Exercises - Section 5-3 - Page 305: 17
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