Answer
a. $0.966$
b. $0.034$
c. $0.108$
Work Step by Step
a. What is the probability that none have autism?
$p=(\frac{87}{88})^3=0.966$
b. What is the probability that at least 1 has autism?
This is the complement of (a): $1-0.966=0.034$
c. Choose 10 children at random, What is the probability that at least 1 has autism?
First find the case of 0 has autism: $p=(\frac{87}{88})^10=0.892$
then the probability that at least 1 has autism is the complement: $1-0.892=0.108$
