Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 4 - Probability and Counting Rules - 4-3 The Multiplication Rules and Conditional Probability - Exercises 4-3 - Page 225: 34


a. $0.359$ b. $0.207$ c. $0.959$ d. $0.305$

Work Step by Step

Calculate the sums of all rows and columns. Total = 17927 a. What is the probability that it was from Ethiopia given that it was from 2010? total from 2010=6996, $p=2513/6996=0.359$ b. What is the probability that it was from Russia and in 2006? $p=3706/17927=0.207$ c. What is the probability that it did not occur in 2006 and was not from Ethiopia? P(2006 and Ethiopia)=$732/17927=0.041$, P(not2006 and not Ethiopia)=$1-0.041=0.959$ d. Choose two adoptions at random; what is the probability that they were both from China? P(China)=$9894/17927=0.552$ As the total is large, the two adoptions can be regarded as independent. P(2 from China)=$0.552^2=0.305$
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