Answer
a. $0.216$
b. $0.064$
c. $0.936$
Work Step by Step
a. All have assistantships
$p=0.6^3=0.216$
b. None has an assistantship
$p=(1-0.6)^3=0.064$
c. At least 1 has an assistantship
This is the complement of case (b) $p=1-0.064=0.936$
Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition
by Bluman, Allan
Published by
McGraw-Hill Education
ISBN 10:
0078136334
ISBN 13:
978-0-07813-633-7
Chapter 4 - Probability and Counting Rules - 4-3 The Multiplication Rules and Conditional Probability - Exercises 4-3 - Page 225: 42
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