Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 4 - Probability and Counting Rules - 4-3 The Multiplication Rules and Conditional Probability - Exercises 4-3 - Page 225: 42


a. $0.216$ b. $0.064$ c. $0.936$

Work Step by Step

a. All have assistantships $p=0.6^3=0.216$ b. None has an assistantship $p=(1-0.6)^3=0.064$ c. At least 1 has an assistantship This is the complement of case (b) $p=1-0.064=0.936$
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