Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

a. $0.216$ b. $0.064$ c. $0.936$
a. All have assistantships $p=0.6^3=0.216$ b. None has an assistantship $p=(1-0.6)^3=0.064$ c. At least 1 has an assistantship This is the complement of case (b) $p=1-0.064=0.936$