#### Answer

0.116

#### Work Step by Step

Model I accounts for 80% and 10% are defective, hence:
P(Model-I is defective) = 0.8 x 0.1 = 0.08
Model II accounts for 20% and 18% are defective, hence:
P(Model-I is defective) = 0.2 x 0.18 = 0.036
P(Any of the items is defective) = 0.08 + 0.036 = 0.116