Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 11 - Other Chi-Square Tests - 11-2 Testing Using Contingency Tables - Exercises 11-2 - Page 634: 8

Answer

8. Step 1: $H_0$ :Movie admissions are independent from ethnicity $H_1$: Movie admissions are dependent upon ethnicity. Step 2: Since α=0.05, the critical value using Table G with (4-1)(2-1) = (3)(1) =3 degrees of freedom is 7.815. Step 3: Expected Value: $E_1,1$ = $\frac{(1472)(1845)}{(2943)}$ = 922.81 $E_1,2$ = $\frac{(1472)(537)}{(2943)}$ = 268.59 $E_1,3$ = $\frac{(1472)(345)}{(2943)}$= 172.56 $E_1,4$ = $\frac{(1472)(216)}{(2943)}$ = 108.04 $E_2,1$ = $\frac{(1471)(1845)}{(2943)}$ = 922.19 $E_2,2$ = $\frac{(1471)(537)}{(2943)}$ = 268.41 $E_2,3$ = $\frac{(1471)(345)}{(2943)}$ = 172.44 $E_2,4$ = $\frac{(1471)(216)}{(2943)}$ = 107.96 Test Value : χ2 = Σ $\frac{(O-E)^{2}}{E}$ = $\frac{(936-922.81)^{2}}{922.81}$ + $\frac{(240-268.59)^{2}}{268.59}$ + $\frac{(195-172.56)^{2}}{172.56}$ + $\frac{(101-108.04)^{2}}{108.04}$ + $\frac{(909-922.19)^{2}}{922.19}$ + $\frac{(297-268.41)^{2}}{268.41}$ + $\frac{(150-172.44)^{2}}{172.44}$ + $\frac{(115-107.96)^{2}}{107.96}$ + =0.188+3.044+2.919+0.458+0.189+3.046+2.921+0.459 =13.222 Step 4: Since 13.222 > 7.815, the decision is to reject the null hypothesis. Step 5: There is enough evidence to claim that the movie admissions are dependent upon ethnicity.
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